Thus up to multiplicative dependence there is at most one way for a solution to be found. Sign up to join this community. The best answers are voted up and rise to the top. Asked 6 years, 5 months ago. Active 4 years, 1 month ago. Viewed 1k times. Improve this question. Community Bot 1 2 2 silver badges 3 3 bronze badges. This satisfy me as an answer, but i'll leave this open in case someone has some great idea of how to show this without Schanuel.
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Sample EA problems and more. For any positive integer n, the sum of the first n positive integers. Find Similar Topics. Show Tags. Own Kudos [? For any positive integer n, the sum of the first n positive integers [ permalink ] Updated on: Jun 10, pm. Add Notes. Hide Show timer Statistics. What is the sum of all the even integers between 99 and ? Originally posted by CharmWithSubstance on May 11, pm.
Last edited by Bunuel on Jun 10, pm, edited 2 times in total. Most Helpful Expert Reply. Re: For any positive integer n, the sum of the first n positive integers [ permalink ] Feb 20, am. Now, the sum of the elements in any evenly spaced set is the mean average multiplied by the number of terms.
Answer: B. Now, the sum of the integers from 50 to , inclusive equals to the sum of the integers from 1 to , inclusive minus the sum of the integers from 1 to 49, inclusive. Hope it helps. Re: For any positive integer n, the sum of the first n positive integers [ permalink ] Apr 27, pm. Re: For any positive integer n, the sum of the first n positive integers [ permalink ] Dec 19, pm. Re: For any positive integer n, the sum of the first n positive integers [ permalink ] Feb 25, pm.
You can also multiply by the average at the end to get the sum. Answer choice C with a presumed typo in the unit digit? Hope this helps! Re: For any positive integer n, the sum of the first n positive integers [ permalink ] Apr 19, pm. Re: For any positive integer n, the sum of the first n positive integers [ permalink ] Jun 10, pm.
The term inside the bracket represents a sequence of positive integers. But, we cannot apply the given formula directly since these do not represent the FIRST n positive integers. The only value that fits is 20, The correct answer option is B.
Hope that helps! Aravind B T. Most Helpful Community Reply. Re: For any positive integer n, the sum of the first n positive integers [ permalink ] Aug 26, pm. We can understand the sum of even integers between 99 and by somehow rewriting in terms of the expression they gave us. They were using the terminology of the first n positive integers.
OK, well sum of even integers between 99 and is the same as between and - inclusive. Same as the sum of the even integers up to - sum of the even integers up to 98 Same as the sum of the first even integers - sum of the first 49 even integers So how do we translate this to the expression we were given?
We need to translate our "even" integer expression into "positive integers" expression with our formula. Re: For any positive integer n, the sum of the first n positive integers [ permalink ] Nov 16, am.
Show Spoiler. General Discussion. Re: For any positive integer n, the sum of the first n positive integers [ permalink ] May 11, pm.
Re: For any positive integer n, the sum of the first n positive integers [ permalink ] May 12, am. Re: For any positive integer n, the sum of the first n positive integers [ permalink ] Jul 11, am. And since we have a formula for the first "n" integers and not for some random range of integers we try to reduce what we're asked to find to this form Hope this answers your question. Re: For any positive integer n, the sum of the first n positive integers [ permalink ] Jul 11, pm. Re: For any positive integer n, the sum of the first n positive integers [ permalink ] Oct 22, pm.
A 10, B 20, C 22, D 40, E 45, Re: For any positive integer n, the sum of the first n positive integers [ permalink ] Dec 07, pm. Re: For any positive integer n, the sum of the first n positive integers [ permalink ] Dec 08, am. Re: For any positive integer n, the sum of the first n positive integers [ permalink ] Dec 09, am.
So what do we do? We find the sum of first numbers and subtract the sum of first 49 numbers from it. That will give us the sum of numbers from 50 to Note that we subtract 49 numbers because 50 is part of our series. We need it so we do not subtract it.
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